multiply by the reciprocal to divide
divide fractions by fractions

Find the quotient: $$\mathtt{\frac{1}{4} \div \frac{5}{6} =}$$ ?

Write the equivalent fractions with a common denominator of 24.

$$\mathtt{\frac{1}{4}}$$ = $$\frac{\FormInput[][math_wrap][]{partial1_wrap}\FormInput{partial1}}{\FormInput[][math_wrap][]{partial2_wrap}\FormInput{partial2}}$$   $$\mathtt{\frac{5}{6}}$$ = $$\frac{\FormInput[][math_wrap][]{partial3_wrap}\FormInput{partial3}}{\FormInput[][math_wrap][]{partial4_wrap}\FormInput{partial4}}$$

Divide the numerators from left to right. This is the quotient. Write the quotient in simplest form.

$$\frac{\FormInput[][math_wrap][]{partial5_wrap}\FormInput{partial5}}{\FormInput[][math_wrap][]{partial6_wrap}\FormInput{partial6}}$$ = $$\frac{\FormInput[][math_wrap][]{partial7_wrap}\FormInput{partial7}}{\FormInput[][math_wrap][]{partial8_wrap}\FormInput{partial8}}$$

solve problems with division of fractions by fractions

How much chocolate will each person get if 3 people share $$\mathtt{\frac{1}{2}}$$ pound of chocolate equally?

One half pound will be divided equally by 3 people. Write the division problem. (Write 3 as a fraction.)

$$\frac{\FormInput[][math_wrap][]{partial9_wrap}\FormInput{partial9}}{\FormInput[][math_wrap][]{partial10_wrap}\FormInput{partial10}}$$ ÷ $$\frac{\FormInput[][math_wrap][]{partial11_wrap}\FormInput{partial11}}{\FormInput[][math_wrap][]{partial12_wrap}\FormInput{partial12}}$$

Rewrite the division problem so that the fractions are in the same "units." This means to use 2 as the common denominator.

$$\frac{\FormInput[][math_wrap][]{partial13_wrap}\FormInput{partial13}}{\FormInput[][math_wrap][]{partial14_wrap}\FormInput{partial14}}$$ ÷ $$\frac{\FormInput[][math_wrap][]{partial15_wrap}\FormInput{partial15}}{\FormInput[][math_wrap][]{partial16_wrap}\FormInput{partial16}}$$

The answer is the quotient of the numerators.
Write the quotient.

$$\frac{\FormInput[][math_wrap][]{partial17_wrap}\FormInput{partial17}}{\FormInput[][math_wrap][]{partial18_wrap}\FormInput{partial18}}$$

If each person gets $$\frac{\FormInput[][math_wrap][]{partial20_wrap}\FormInput{partial20}}{\FormInput[][math_wrap][]{partial21_wrap}\FormInput{partial21}}$$ pound, then people get $$\frac{\FormInput[][math_wrap][]{partial23_wrap}\FormInput{partial23}}{\FormInput[][math_wrap][]{partial24_wrap}\FormInput{partial24}}$$ pound.

solve problems with division of fractions by fractions

How many $$\mathtt{\frac{3}{4}}$$-cup servings are in $$\mathtt{\frac{2}{3}}$$ of a cup of yogurt?

Write the division expression that represents this problem.

$$\frac{\FormInput[][math_wrap][]{partial25_wrap}\FormInput{partial25}}{\FormInput[][math_wrap][]{partial26_wrap}\FormInput{partial26}}$$ ÷ $$\frac{\FormInput[][math_wrap][]{partial27_wrap}\FormInput{partial27}}{\FormInput[][math_wrap][]{partial28_wrap}\FormInput{partial28}}$$

Write the division problem using a common denominator of 12.

$$\frac{\FormInput[][math_wrap][]{partial29_wrap}\FormInput{partial29}}{\FormInput[][math_wrap][]{partial30_wrap}\FormInput{partial30}}$$ ÷ $$\frac{\FormInput[][math_wrap][]{partial31_wrap}\FormInput{partial31}}{\FormInput[][math_wrap][]{partial32_wrap}\FormInput{partial32}}$$

$$\frac{\FormInput[][math_wrap][]{partial33_wrap}\FormInput{partial33}}{\FormInput[][math_wrap][]{partial34_wrap}\FormInput{partial34}}$$

There is $$\frac{\FormInput[][math_wrap][]{partial35_wrap}\FormInput{partial35}}{\FormInput[][math_wrap][]{partial36_wrap}\FormInput{partial36}}$$ of a $$\mathtt{\frac{3}{4}}$$-cup serving in $$\mathtt{\frac{2}{3}}$$ of a cup of yogurt.
$$\mathtt{\frac{4}{5}}$$ ÷ $$\mathtt{\frac{1}{5}}$$ = $$\frac{\FormInput[][math_wrap][]{partial37_wrap}\FormInput{partial37}}{\FormInput[][math_wrap][]{partial38_wrap}\FormInput{partial38}}$$   $$\mathtt{\frac{1}{8}}$$ ÷ $$\mathtt{\frac{1}{3}}$$ = $$\frac{\FormInput[][math_wrap][]{partial39_wrap}\FormInput{partial39}}{\FormInput[][math_wrap][]{partial40_wrap}\FormInput{partial40}}$$
$$\mathtt{\frac{3}{4}}$$ ÷ $$\mathtt{\frac{1}{2}}$$ = $$\frac{\FormInput[][math_wrap][]{partial41_wrap}\FormInput{partial41}}{\FormInput[][math_wrap][]{partial42_wrap}\FormInput{partial42}}$$   $$\mathtt{\frac{5}{6}}$$ ÷ $$\mathtt{\frac{1}{8}}$$ = $$\frac{\FormInput[][math_wrap][]{partial43_wrap}\FormInput{partial43}}{\FormInput[][math_wrap][]{partial44_wrap}\FormInput{partial44}}$$